About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us CreatorsIt is actually very simple if you notice that the quadratic polynomial in mathy/math is the square of a linear one mathx^2 y^2 2y 1 = x^2 (y^2 2y 1)/math math\implies x^2 y^2 2y 1 = x^2 (y 1)^2/math math\implie2) is perpendicular to the radius, so m × m tangent = − 1 m tangent = − 1 m = − 1 5 3 = − 3 5 The gradient for the tangent is m tangent = − 3 5 Show Answer Given a circle with the central coordinates (a;
Class 9 Polynomial 2 Coordinate Geometry Linear Equation In Two Variables Euclid S Geometry Lines And Angles Notes