Math Graph the quadratic functions y = 2x^2 and y = 2x^2 4 on a separate piece of paper Using those graphs, compare G y= 2x 2 H y = 2x 4 I y= 4x 4 Answers 2 Get Other questions on the subject Mathematics Mathematics, 1630, shanua What is the difference between regular convex and concave polygons Answers 1 continue Mathematics, 21PreAlgebra Graph y=2x2 y = 2x 2 y = 2 x 2 Use the slopeintercept form to find the slope and yintercept Tap for more steps The slopeintercept form is y = m x b y = m x b, where m m is the slope and b b is the yintercept y = m x b y = m x b Find the values of m m and b b using the form y = m x b y = m x b

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Y=x^2+2/x
Y=x^2+2/x- The equation y = 2x2 can be written as y = 2x (2) Adding a negative number is the same as subtraction Eg 2 (3) = 23 The equation y = 2x (2) is in the form y = mxb where m = 2 is the slope b = 2 is the y intercept Therefore the final answer is simply 2 See the explanation Suppose x=3 then 2x2=8 So the inequality of y




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Hint Drag to pan Mouse wheel to zoomStep by step solution of a set of 2, 3 or 4 Linear Equations using the Substitution Method y=2x5 ;Divide y8 by 2 x=\frac {\sqrt {2y16}} {2} x=\frac {\sqrt {2y16}} {2} Take the square root of both sides of the equation 2x^ {2}8=y Swap sides so that all variable terms are on the left hand side 2x^ {2}8y=0 Subtract y from both sides 2x^ {2}y8=0 Quadratic equations like this one, with an x^ {2} term but no x term, can still be
Refer to the explanation y=22x is the same as y=2x2, which is the slopeintercept form of a linear equation, y=mxb, where m is the slope and b is the yintercept In the given equation, m=2 and b=2 In order to graph a linear equation, you need to find at least two points on the graph, plot the points on the graph, then draw a straight line through those points51 Find the Vertex of y = 2x 2 5x2 Parabolas have a highest or a lowest point called the Vertex Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) We know this even before plotting "y" because the coefficient of the first term, 2 , is positive (greater than zero)Y=2x2 6x3y=6 consists of two lines that a intersect at one point b do not intersect c are not in the same place d intersect in an infinite number of points Answer by KMST(52) (Show Source) You can put this solution on YOUR website!
Steps for Solving Linear Equation 2xy=8 2 x y = 8 Subtract y from both sides Subtract y from both sides 2x=8y 2 x = 8 − y Divide both sides by 2 Divide both sides by 2 y= 2x^2 7x 3 (x)(y) A)The quantity in Column A is greater B)The quantity in Column B is greater C)The two quantities are equal D)The relationship cannot be determined from the information given Practice Questions Question 5 PageSimple and best practice solution for y=2x2 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,



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Free Parabola calculator Calculate parabola foci, vertices, axis and directrix stepbystepFree linear equation calculator solve linear equations stepbystep 1 Solve the system of equations y=2x^23 y=3x1 a)no solution b)(1/2,5),(2,5/2) c)(1/2,5/2),(2,5)**** d)(1/2,5/2),(2,5) 2 How many real number solutions are there to the equation 0=3x^2x4?



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Steps for Solving Linear Equation y=2x3 y = − 2 x − 3 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x3=y − 2 x − 3 = y Add 3 to both sides Add 3 to both sidesY=2x2 Tiger Algebra SolverThis video shows how to take the graph of y = x^2 and stretch it vertically by a factor of 2




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Get stepbystep solutions from expert tutors as fast as 1530 minutes #y=2x^2# #2y^2y=2x^22y^2# #2(r(theta)sin(theta))^2r(theta)sin(theta)=2(r(theta))^2# #2(r(theta))^2sin^2(theta)r(theta)sin(theta)=2(r(theta))^2#Precalculus Find the Vertex y=2x^2 y = 2x2 y = 2 x 2 Rewrite the equation in vertex form Tap for more steps Complete the square for 2 x 2 2 x 2 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 2, b = 0, c = 0 a = 2, b = 0, c = 0




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Add 2x 2 x to both sides of the equation y = 2 2x y = 2 2 x Rewrite in slopeintercept form Tap for more steps math Graph the quadratic functions y = 2x^2 and y = 2x^2 4 on a separate piece of paper Using those graphs, compare and contrast the shape and position of the graphs I would suggest you graph the two functions on the same grid, not on separate pieces of paper You will be able to answer the questions so much easierGiven $$\begin{align} f(x,y) &= 2x^23xy4y^27x11y \\03cm \end{align} $$ Find the critical points of f A point {eq}\,\, (x, y) \,\, {/eq} is critical, when it satisfies that the firstorder




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